Calculate number of moles of product would be produced by complete converions of 0.15 the 2Mg:
2Mg + O2 ----%26gt; 2Mgo
What are the steps? Can i simply multiply the .15 by all of the reactants and products?How do i work this stoichiometry problem?
to do this. you need a ratio of the given element and the non given element. so its .15 divided by 2 = x divided by 2 ( because there is 2 Mg and 2 MgO)
then solve for x. the answer should be .15 mols
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