Twenty-five different positive integers add to 2008. What is the largest value that the least of them can have?How do you work this out algebraically?
The largest value of the lowest number would be when all the numbers are in sequence.
x + (x+1) + (x+2) + 鈥?+ (x+23) + (x+24) = 2008
25x + 300 = 2008
25x = 1708
x = 68.32
The largest value of the lowest number is 68.
68 + 69 + 70 + 鈥?+ 91 + 92 = 2000
68 + 69 + 70 + 鈥?+ 91 + 100 = 2008How do you work this out algebraically?
(n + 1)C2 = 2008
n(n + 1) = 4016
n^2 + n = 4016
n^2 + n - 4016 = 0
Looks like you'll need the quadratic formula.
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